Difference between revisions of "1999 AMC 8 Problems/Problem 22"

(Created page with "Let <math>f</math> represent one fish, <math>l</math> a loaf of bread, and <math>r</math> a bag of rice. Then: <math>3f=2l</math> <math>l=4r</math> Substituting <math>l</math> f...")
 
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Let <math>f</math> represent one fish, <math>l</math> a loaf of bread, and <math>r</math> a bag of rice. Then:
 
Let <math>f</math> represent one fish, <math>l</math> a loaf of bread, and <math>r</math> a bag of rice. Then:
<math>3f=2l</math>
+
<math>3f=2l</math>,
 
<math>l=4r</math>
 
<math>l=4r</math>
  
Substituting <math>l</math> from the second equation back into the first gives us <math>3f=8r</math>. So each fish is worth <math>\frac{8}{3}</math> bags of rice, or <math>2 \frac{2}{3}=>\boxed{D}</math>.
+
Substituting <math>l</math> from the second equation back into the first gives us <math>3f=8r</math>. So each fish is worth <math>\frac{8}{3}</math> bags of rice, or <math>2 \frac{2}{3}\Rightarrow \boxed{D}</math>.

Revision as of 19:59, 28 July 2011

Let $f$ represent one fish, $l$ a loaf of bread, and $r$ a bag of rice. Then: $3f=2l$, $l=4r$

Substituting $l$ from the second equation back into the first gives us $3f=8r$. So each fish is worth $\frac{8}{3}$ bags of rice, or $2 \frac{2}{3}\Rightarrow \boxed{D}$.

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