Difference between revisions of "1999 AMC 8 Problems/Problem 4"
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After 4 hours, we see that Bjorn biked 45 miles, and Alberto biked 60. Thus the answer is <math>60-45=15</math> <math>\boxed{\text{(A)}}</math>. | After 4 hours, we see that Bjorn biked 45 miles, and Alberto biked 60. Thus the answer is <math>60-45=15</math> <math>\boxed{\text{(A)}}</math>. | ||
+ | ==Solution 2== | ||
+ | We see that each dot is <math>15</math> units away from the nearest one above it. So the answer is <math>\boxed{\text{A}} </math>. | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=1999|num-b=3|num-a=5}} | {{AMC8 box|year=1999|num-b=3|num-a=5}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 20:02, 14 April 2017
Contents
Problem
The diagram shows the miles traveled by bikers Alberto and Bjorn. After four hours, about how many more miles has Alberto biked than Bjorn?
Solution
After 4 hours, we see that Bjorn biked 45 miles, and Alberto biked 60. Thus the answer is .
Solution 2
We see that each dot is units away from the nearest one above it. So the answer is .
See Also
1999 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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