Difference between revisions of "1999 AMC 8 Problems/Problem 7"

(Created page with "The distance between the two exits is 160-40=120. 120*(3/4)=90, so the exit is 90 miles away from the third exit or at the 40+90=130 milepost, so the answer is E.")
 
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The distance between the two exits is 160-40=120. 120*(3/4)=90, so the exit is 90 miles away from the third exit or at the 40+90=130 milepost, so the answer is E.
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===problem==
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The third exit on a highway is located at milepost 40 and the tenth exit is at
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milepost 160. There is a service center on the highway located three-fourths
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of the way from the third exit to the tenth exit. At what milepost would you
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expect to ¯nd this service center?
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(A) 90 (B) 100 (C) 110 (D) 120 (E) 130
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==solution==
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(E) 130:  The distance between the two exits is 160-40=120. 120*(3/4)=90, so the exit is 90 miles away from the third exit or at the 40+90=130 milepost, so the answer is E.
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==See Also==
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{{AMC8 box|year=1999|num-b=6|num-a=8}}

Revision as of 14:56, 4 November 2012

=problem

The third exit on a highway is located at milepost 40 and the tenth exit is at milepost 160. There is a service center on the highway located three-fourths of the way from the third exit to the tenth exit. At what milepost would you expect to ¯nd this service center? (A) 90 (B) 100 (C) 110 (D) 120 (E) 130

solution

(E) 130: The distance between the two exits is 160-40=120. 120*(3/4)=90, so the exit is 90 miles away from the third exit or at the 40+90=130 milepost, so the answer is E.

See Also

1999 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions