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1999 AMC 8 Problems/Problem 7

Revision as of 01:02, 20 June 2011 by CYAX (talk | contribs) (Created page with "The distance between the two exits is 160-40=120. 120*(3/4)=90, so the exit is 90 miles away from the third exit or at the 40+90=130 milepost, so the answer is E.")
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The distance between the two exits is 160-40=120. 120*(3/4)=90, so the exit is 90 miles away from the third exit or at the 40+90=130 milepost, so the answer is E.

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