Difference between revisions of "2000 AMC 10 Problems/Problem 10"
(→Solution) |
5849206328x (talk | contribs) m (→Solution) |
||
Line 7: | Line 7: | ||
==Solution== | ==Solution== | ||
− | From the triangle inequality, <math>2<x<10</math> and <math>2<y<10</math>. The smallest positive number not possible is 10-2, which is 8. | + | From the triangle inequality, <math>2<x<10</math> and <math>2<y<10</math>. The smallest positive number not possible is <math>10-2</math>, which is <math>8</math>. |
<math>\boxed{\text{D}}</math> | <math>\boxed{\text{D}}</math> | ||
Revision as of 21:40, 9 January 2009
Problem
The sides of a triangle with positive area have lengths , , and . The sides of a second triangle with positive area have lengths , , and . What is the smallest positive number that is not a possible value of ?
Solution
From the triangle inequality, and . The smallest positive number not possible is , which is .
See Also
2000 AMC 10 (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |