2000 AMC 10 Problems/Problem 10

Revision as of 19:38, 8 January 2009 by 5849206328x (talk | contribs)

Problem

Solution

The largest possible value for $x$ is $9$. The smallest is $3$.

$9-3=6$.

$8$ is the smallest that cannot be made (of the choices listed)

$\boxed{\text{D}}$

See Also

2000 AMC 10 (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions