Difference between revisions of "2000 AMC 10 Problems/Problem 3"

(New page: <math>x \cdot .8 \cdot .8=32</math> <math>x \cdot .64=32</math> <math>x \cdot \frac{32}{50}=32</math> <math>x=50</math>. B.)
 
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<math>x \cdot .8 \cdot .8=32</math>
 
<math>x \cdot .8 \cdot .8=32</math>
 +
 
<math>x \cdot .64=32</math>
 
<math>x \cdot .64=32</math>
 +
 
<math>x \cdot \frac{32}{50}=32</math>
 
<math>x \cdot \frac{32}{50}=32</math>
 +
 
<math>x=50</math>.
 
<math>x=50</math>.
  
 
B.
 
B.

Revision as of 18:43, 8 January 2009

$x \cdot .8 \cdot .8=32$

$x \cdot .64=32$

$x \cdot \frac{32}{50}=32$

$x=50$.

B.