Difference between revisions of "2000 AMC 10 Problems/Problem 3"

Latest revision as of 23:33, 26 November 2011

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-==Problem==
+#REDIRECT [[2000 AMC 12 Problems/Problem 3]]
-Each day, Jenny ate <math>20\%</math> of the jellybeans that were in her jar at the beginning of that day. At the end of the second day, <math>32</math> remained. How many jellybeans were in the jar originally?
-<math>\mathrm{(A)}\ 40 \qquad\mathrm{(B)}\ 50 \qquad\mathrm{(C)}\ 55 \qquad\mathrm{(D)}\ 60 \qquad\mathrm{(E)}\ 75</math>
-==Solution==
-<math>x(.8)(.8)=32</math>
-<math>x(.64)=32</math>
-<math>x \cdot \frac{32}{50}=32</math>
-<math>x=50</math>
-<math>\boxed{\text{B}}</math>
-==See Also==
-{{AMC10 box|year=2000|num-b=2|num-a=4}}