Difference between revisions of "2000 AMC 10 Problems/Problem 8"

(New page: Let <math>f</math> be the number of freshman and s be the number of sophomores. <math>\frac{2}{5}f=\frac{4}{5}s</math>. <math>f=2s</math>. There are twice as many freshman as sophomores.)
 
Line 5: Line 5:
  
 
There are twice as many freshman as sophomores.
 
There are twice as many freshman as sophomores.
 +
D.

Revision as of 15:02, 7 January 2009

Let $f$ be the number of freshman and s be the number of sophomores.

$\frac{2}{5}f=\frac{4}{5}s$. $f=2s$.

There are twice as many freshman as sophomores. D.

Invalid username
Login to AoPS