Difference between revisions of "2000 AMC 10 Problems/Problem 9"

(New page: <math>|x-2|=p</math> <math>x<2</math>, so <math>2-x=p</math>. <math>x+p=2</math>. <math>x-p=2-2p</math>.)
 
(duplicate)
 
(4 intermediate revisions by 2 users not shown)
Line 1: Line 1:
<math>|x-2|=p</math>
+
#REDIRECT [[2000 AMC 12 Problems/Problem 5]]
<math>x<2</math>, so <math>2-x=p</math>.
 
 
 
<math>x+p=2</math>.
 
<math>x-p=2-2p</math>.
 

Latest revision as of 23:37, 26 November 2011