Difference between revisions of "2000 AMC 10 Problems/Problem 9"

m
(duplicate)
 
(One intermediate revision by one other user not shown)
Line 1: Line 1:
==Problem==
+
#REDIRECT [[2000 AMC 12 Problems/Problem 5]]
 
 
==Solution==
 
 
 
<math>|x-2|=p</math>
 
 
 
<math>x<2</math>, so <math>2-x=p</math>.
 
 
 
<math>x+p=2</math>.
 
 
 
<math>x-p=2-2p</math>.
 
 
 
<math>\boxed{\text{C}}</math>
 
 
 
==See Also==
 
 
 
{{AMC10 box|year=2000|num-b=8|num-a=10}}
 

Latest revision as of 23:37, 26 November 2011