2000 AMC 10 Problems/Problem 9

Revision as of 15:02, 7 January 2009 by BOGTRO (talk | contribs) (New page: <math>|x-2|=p</math> <math>x<2</math>, so <math>2-x=p</math>. <math>x+p=2</math>. <math>x-p=2-2p</math>.)
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$|x-2|=p$ $x<2$, so $2-x=p$.

$x+p=2$. $x-p=2-2p$.

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