Difference between revisions of "2000 AMC 12 Problems/Problem 2"

m (Solution)
(Problem)
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<math>2000(2000^{2000}) =</math>
 
<math>2000(2000^{2000}) =</math>
  
<math> \mathrm{(A) \ 2000^{2001} } \qquad \mathrm{(B) \ 4000^{2000} } \qquad \mathrm{(C) \ 2000^{4000} } \qquad \mathrm{(D) \ 4,000,000^{2000} } \qquad \mathrm{(E) \ 2000^{4,000,000} </math>
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<math> \textbf{(A)} \ 2000^{2001} \qquad \textbf{(B)} \ 4000^{2000} \qquad \textbf{(C)} \ 2000^{4000} \qquad \textbf{(D)} \ 4,000,000^{2000} \qquad \textbf{(E)} \ 2000^{4,000,000}   </math>
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== Solution ==
 
== Solution ==
 
<math> 2000(2000^{2000}) = (2000^{1})(2000^{2000}) = 2000^{2001} \Rightarrow \boxed{A}</math>
 
<math> 2000(2000^{2000}) = (2000^{1})(2000^{2000}) = 2000^{2001} \Rightarrow \boxed{A}</math>

Revision as of 20:19, 23 November 2020

The following problem is from both the 2000 AMC 12 #2 and 2000 AMC 10 #2, so both problems redirect to this page.

Problem

$2000(2000^{2000}) =$

$\textbf{(A)} \ 2000^{2001}  \qquad \textbf{(B)} \ 4000^{2000}  \qquad \textbf{(C)} \ 2000^{4000}  \qquad \textbf{(D)} \ 4,000,000^{2000}  \qquad \textbf{(E)} \ 2000^{4,000,000}$

Solution

$2000(2000^{2000}) = (2000^{1})(2000^{2000}) = 2000^{2001} \Rightarrow \boxed{A}$

See also

2000 AMC 12 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions
2000 AMC 10 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

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