2000 AMC 8 Problems/Problem 24

Revision as of 20:56, 28 July 2011 by Mrdavid445 (talk | contribs) (Created page with "If <math> \angle A = 20^\circ </math> and <math> \angle AFG =\angle AGF </math>, then <math> \angle B+\angle D = </math> <asy> pair A,B,C,D,EE,F,G; A = (0,0); B = (9,4); C = (21...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

If $\angle A = 20^\circ$ and $\angle AFG =\angle AGF$, then $\angle B+\angle D =$

[asy] pair A,B,C,D,EE,F,G; A = (0,0); B = (9,4); C = (21,0); D = (13,-12); EE = (4,-16); F = (13/2,-6); G = (8,0); draw(A--C--EE--B--D--cycle); label("$A$",A,W); label("$B$",B,N); label("$C$",C,E); label("$D$",D,SE); label("$E$",EE,SW); label("$F$",F,WSW); label("$G$",G,NW);[/asy]

$\text{(A)}\ 48^\circ\qquad\text{(B)}\ 60^\circ\qquad\text{(C)}\ 72^\circ\qquad\text{(D)}\ 80^\circ\qquad\text{(E)}\ 90^\circ$