Difference between revisions of "2001 AMC 12 Problems/Problem 3"
(→Solution 2) |
|||
(31 intermediate revisions by 2 users not shown) | |||
Line 1: | Line 1: | ||
{{duplicate|[[2001 AMC 12 Problems|2001 AMC 12 #3]] and [[2001 AMC 10 Problems|2001 AMC 10 #9]]}} | {{duplicate|[[2001 AMC 12 Problems|2001 AMC 12 #3]] and [[2001 AMC 10 Problems|2001 AMC 10 #9]]}} | ||
− | == Problem == | + | ==Problem== |
The state income tax where Kristin lives is levied at the rate of <math>p\%</math> of the first | The state income tax where Kristin lives is levied at the rate of <math>p\%</math> of the first | ||
<math>\textdollar 28000</math> of annual income plus <math>(p + 2)\%</math> of any amount above <math>\textdollar 28000</math>. Kristin | <math>\textdollar 28000</math> of annual income plus <math>(p + 2)\%</math> of any amount above <math>\textdollar 28000</math>. Kristin | ||
Line 9: | Line 9: | ||
<math>\text{(A)}\,\textdollar 28000 \qquad \text{(B)}\,\textdollar 32000 \qquad \text{(C)}\,\textdollar 35000 \qquad \text{(D)}\,\textdollar 42000 \qquad \text{(E)}\,\textdollar 56000</math> | <math>\text{(A)}\,\textdollar 28000 \qquad \text{(B)}\,\textdollar 32000 \qquad \text{(C)}\,\textdollar 35000 \qquad \text{(D)}\,\textdollar 42000 \qquad \text{(E)}\,\textdollar 56000</math> | ||
− | + | ==Solution 1== | |
− | |||
− | |||
− | |||
Let the income amount be denoted by <math>A</math>. | Let the income amount be denoted by <math>A</math>. | ||
Line 27: | Line 24: | ||
So the answer is <math>\boxed{B}</math> | So the answer is <math>\boxed{B}</math> | ||
− | |||
− | Let <math>A</math> be Kristin's annual income. Notice that <cmath>A = p%</cmath> | + | ==Solution 2== |
+ | |||
+ | Let <math>A</math>, <math>T</math> be Kristin's annual income and the income tax total, respectively. Notice that | ||
+ | <cmath>\begin{align*} | ||
+ | T &= p\%\cdot28000 + (p + 2)\%\cdot(A - 28000) \\ | ||
+ | &= [p\%\cdot28000 + p\%\cdot(A - 28000)] + 2\%\cdot(A - 28000) \\ | ||
+ | &= p\%\cdot A + 2\%\cdot(A - 28000) | ||
+ | \end{align*}</cmath> | ||
+ | We are also given that <cmath>T = (p + 0.25)\%\cdot A = p\%\cdot A + 0.25\%\cdot A</cmath> | ||
+ | Thus, <cmath>p\%\cdot A + 2\%\cdot(A - 28000) = p\%\cdot A + 0.25\%\cdot A</cmath> <cmath>2\%\cdot(A - 28000) = 0.25\%\cdot A</cmath> | ||
+ | Solve for <math>A</math> to obtain <math>A = 32000</math>. <math>\boxed{B}</math> | ||
+ | |||
+ | ~ Nafer | ||
== See Also == | == See Also == |
Latest revision as of 20:07, 1 May 2021
- The following problem is from both the 2001 AMC 12 #3 and 2001 AMC 10 #9, so both problems redirect to this page.
Contents
Problem
The state income tax where Kristin lives is levied at the rate of of the first of annual income plus of any amount above . Kristin noticed that the state income tax she paid amounted to of her annual income. What was her annual income?
Solution 1
Let the income amount be denoted by .
We know that .
We can now try to solve for :
So the answer is
Solution 2
Let , be Kristin's annual income and the income tax total, respectively. Notice that We are also given that Thus, Solve for to obtain .
~ Nafer
See Also
2001 AMC 12 (Problems • Answer Key • Resources) | |
Preceded by Problem 2 |
Followed by Problem 4 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
2001 AMC 10 (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.