Difference between revisions of "2002 AIME II Problems/Problem 1"
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Revision as of 03:32, 6 December 2019
Problem
Given that
How many distinct values of 
are possible?
Solution
We express the numbers as 
and 
. From this, we have
Because 
and 
are digits, and and are both between 1 and 9 (from condition 1), there are 
possible values (since all digits except 
can be expressed this way).
See also
| 2002 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
