Difference between revisions of "2002 AIME I Problems/Problem 10"

m
m (See also)
Line 6: Line 6:
  
 
== See also ==
 
== See also ==
* [[2002 AIME I Problems/Problem 9| Previous problem]]
+
{{AIME box|year=2002|n=I|num-b=9|num-a=11}}
 
 
* [[2002 AIME I Problems/Problem 11| Next problem]]
 
 
 
* [[2002 AIME I Problems]]
 

Revision as of 15:14, 25 November 2007

Problem

In the diagram below, angle $ABC$ is a right angle. Point $D$ is on $\overline{BC}$, and $\overline{AD}$ bisects angle $CAB$. Points $E$ and $F$ are on $\overline{AB}$ and $\overline{AC}$, respectively, so that $AE=3$ and $AF=10$. Given that $EB=9$ and $FC=27$, find the integer closest to the area of quadrilateral $DCFG$.

AIME 2002I Problem 10.png

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See also

2002 AIME I (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions