Difference between revisions of "2002 AIME I Problems/Problem 7"

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(I looked it up on Wikipedia, and corrected the binomial expansion.)
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The Binomial Expansion is valid for exponents that are not integers. That is, for all real numbers <math>x,y</math> and <math>r</math> with <math>|x|>|y|</math>,
 
The Binomial Expansion is valid for exponents that are not integers. That is, for all real numbers <math>x,y</math> and <math>r</math> with <math>|x|>|y|</math>,
  
<cmath>(x+y)^r=x^r+rx^{r-1}y+\dfrac{r(r-1)}{2}x^{r-2}+\dfrac{r(r-1)(r-2)}{3!}x^{r-3}y\cdots</cmath>
+
<cmath>(x+y)^r=x^r+rx^{r-1}y+\dfrac{r(r-1)}{2}x^{r-2}y^2+\dfrac{r(r-1)(r-2)}{3!}x^{r-3}y^3 \cdots</cmath>
  
 
What are the first three digits to the right of the decimal point in the decimal representation of <math>(10^{2002}+1)^{\frac{10}{7}}</math>?
 
What are the first three digits to the right of the decimal point in the decimal representation of <math>(10^{2002}+1)^{\frac{10}{7}}</math>?
  
 
== Solution ==
 
== Solution ==
{{solution}}
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<math>1^n</math> will always be 1, so we can cut out those terms, and we now have
 +
 
 +
<cmath>10^{2860}+\dfrac{10}{7}10^{858}+\dfrac{15}{49}10^{-1144}+\cdots</cmath>
 +
 
 +
Since the exponent in the 10 goes down extremely fast, we just need to consider the first few terms. Also, we can cut the <math>10^{2860}</math> out, so we need to find the first three digits after the decimal in
 +
 
 +
<cmath>\dfrac{10}{7}10^{858}</cmath>.
 +
 
 +
Since the repeating decimal of <math>\dfrac{10}{7}</math> repeats every 6 digits, we can cut out a lot of 6's from 858 to get
 +
 
 +
<math>\dfrac{10}{7}</math>.
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 +
That is the same as <math>1+\dfrac{3}{7}</math>, and the first three digits after <math>\dfrac{3}{7}</math> are <math>\boxed{428}</math>.
  
 
== See also ==
 
== See also ==
 
{{AIME box|year=2002|n=I|num-b=6|num-a=8}}
 
{{AIME box|year=2002|n=I|num-b=6|num-a=8}}

Revision as of 09:18, 5 May 2008

Problem

The Binomial Expansion is valid for exponents that are not integers. That is, for all real numbers $x,y$ and $r$ with $|x|>|y|$,

\[(x+y)^r=x^r+rx^{r-1}y+\dfrac{r(r-1)}{2}x^{r-2}y^2+\dfrac{r(r-1)(r-2)}{3!}x^{r-3}y^3 \cdots\]

What are the first three digits to the right of the decimal point in the decimal representation of $(10^{2002}+1)^{\frac{10}{7}}$?

Solution

$1^n$ will always be 1, so we can cut out those terms, and we now have

\[10^{2860}+\dfrac{10}{7}10^{858}+\dfrac{15}{49}10^{-1144}+\cdots\]

Since the exponent in the 10 goes down extremely fast, we just need to consider the first few terms. Also, we can cut the $10^{2860}$ out, so we need to find the first three digits after the decimal in

\[\dfrac{10}{7}10^{858}\].

Since the repeating decimal of $\dfrac{10}{7}$ repeats every 6 digits, we can cut out a lot of 6's from 858 to get

$\dfrac{10}{7}$.

That is the same as $1+\dfrac{3}{7}$, and the first three digits after $\dfrac{3}{7}$ are $\boxed{428}$.

See also

2002 AIME I (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions