2002 AIME I Problems/Problem 7

Revision as of 09:18, 5 May 2008 by 1=2 (talk | contribs) (I looked it up on Wikipedia, and corrected the binomial expansion.)

Problem

The Binomial Expansion is valid for exponents that are not integers. That is, for all real numbers $x,y$ and $r$ with $|x|>|y|$,

\[(x+y)^r=x^r+rx^{r-1}y+\dfrac{r(r-1)}{2}x^{r-2}y^2+\dfrac{r(r-1)(r-2)}{3!}x^{r-3}y^3 \cdots\]

What are the first three digits to the right of the decimal point in the decimal representation of $(10^{2002}+1)^{\frac{10}{7}}$?

Solution

$1^n$ will always be 1, so we can cut out those terms, and we now have

\[10^{2860}+\dfrac{10}{7}10^{858}+\dfrac{15}{49}10^{-1144}+\cdots\]

Since the exponent in the 10 goes down extremely fast, we just need to consider the first few terms. Also, we can cut the $10^{2860}$ out, so we need to find the first three digits after the decimal in

\[\dfrac{10}{7}10^{858}\].

Since the repeating decimal of $\dfrac{10}{7}$ repeats every 6 digits, we can cut out a lot of 6's from 858 to get

$\dfrac{10}{7}$.

That is the same as $1+\dfrac{3}{7}$, and the first three digits after $\dfrac{3}{7}$ are $\boxed{428}$.

See also

2002 AIME I (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions