Difference between revisions of "2002 AMC 12A Problems/Problem 4"

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{{AMC 12 box|year=2002|ab=A|num-b=3|num-a=5}}

Revision as of 14:38, 17 October 2007

Problem

Find the degree measure of an angle whose complement is 25% of its supplement.

$\mathrm{(A) \ 48 } \qquad \mathrm{(B) \ 60 } \qquad \mathrm{(C) \ 75 } \qquad \mathrm{(D) \ 120 } \qquad \mathrm{(E) \ 150 }$


Solution

$4(90-x)=(180-x)$

$360-4x=180-x$

$3x=180$

$x=60 \Rightarrow \mathrm {(B)}$

See Also

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