Difference between revisions of "2002 AMC 8 Problems/Problem 24"

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==See Also==
 
==See Also==
 
{{AMC8 box|year=2002|num-b=23|num-a=25}}
 
{{AMC8 box|year=2002|num-b=23|num-a=25}}
This problem is copyrighted by the MAA. Thanks for listening.
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Revision as of 18:22, 24 September 2016

Problem

Miki has a dozen oranges of the same size and a dozen pears of the same size. Miki uses her juicer to extract 8 ounces of pear juice from 3 pears and 8 ounces of orange juice from 2 oranges. She makes a pear-orange juice blend from an equal number of pears and oranges. What percent of the blend is pear juice?

$\text{(A)}\ 30\qquad\text{(B)}\ 40\qquad\text{(C)}\ 50\qquad\text{(D)}\ 60\qquad\text{(E)}\ 70$

Solution

A pear gives $8/3$ ounces of juice per pear. An orange gives $8/2=4$ ounces of juice per orange. If the pear-orange juice blend used one pear and one orange each, the percentage of pear juice would be

\[\frac{8/3}{8/3+4} \times 100 = \frac{8}{8+12} \times 100  = \boxed{\text{(B)}\ 40}\]

See Also

2002 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 23
Followed by
Problem 25
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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