2003 AIME II Problems/Problem 15

Revision as of 19:04, 9 July 2006 by Joml88 (talk | contribs) (Problem)

Problem

In $\triangle ABC, AB = 360, BC = 507,$ and $CA = 780.$ Let $M be the midpoint of <math> \overline{CA},$ and let $D$ be the point on $\overline{CA}$ such that $\overline{BD}$ bisects angle $ABC.$ Let $F$ be the point on $\overline{BC}$ such that $\overline{DF} \perp \overline{BD}.$ Suppose that $\overline{DF}$ meets $\overline{BM}$ at $E.$ The ratio $DE: EF$ can be written in the form $m/n,$ where $m$ and $n$ are relatively prime positive integers. Find $m + n.$

Solution

See also

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