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−  == Problem ==
 +  #REDIRECT[[2003 AMC 12A Problems/Problem 2]] 
−  Members of the Rockham Soccer League buy socks and Tshirts. Socks cost $4 per pair and each Tshirt costs $5 more than a pair of socks. Each member needs one pair of socks and a shirt for home games and another pair of socks and a shirt for away games. If the total cost is $2366, how many members are in the League?
 
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−  <math> \mathrm{(A) \ } 77\qquad \mathrm{(B) \ } 91\qquad \mathrm{(C) \ } 143\qquad \mathrm{(D) \ } 182\qquad \mathrm{(E) \ } 286 </math>
 
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−  == Solution ==
 
−  Since Tshirts cost <math>5</math> dollars more than a pair of socks, Tshirts cost <math>5+4=9</math> dollars.
 
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−  Since each member needs <math>2</math> pairs of socks and <math>2</math> Tshirts, the total cost for <math>1</math> member is <math>2(4+9)=26</math> dollars.
 
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−  Since <math>2366</math> dollars was the cost for the club, and <math>26</math> was the cost per member, the number of members in the League is <math>\frac{2366}{26}=91 \Rightarrow B</math>.
 
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−  == See also ==
 
−  {{AMC10 boxyear=2003ab=Anumb=1numa=3}}
 
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−  [[Category:Introductory Algebra Problems]]  