Difference between revisions of "2003 AMC 10B Problems/Problem 5"
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| + | {{duplicate|[[2003 AMC 12B Problems|2003 AMC 12B #4]] and [[2003 AMC 10B Problems|2003 AMC 10B #5]]}} | ||
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==Problem== | ==Problem== | ||
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==See Also== | ==See Also== | ||
| + | {{AMC12 box|year=2003|ab=B|num-b=3|num-a=5}} | ||
{{AMC10 box|year=2003|ab=B|num-b=4|num-a=6}} | {{AMC10 box|year=2003|ab=B|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 00:13, 5 January 2014
- The following problem is from both the 2003 AMC 12B #4 and 2003 AMC 10B #5, so both problems redirect to this page.
Problem
Moe uses a mower to cut his rectangular 
-foot by 
-foot lawn. The swath he cuts is 
inches wide, but he overlaps each cut by 
inches to make sure that no grass is missed. He walks at the rate of 
feet per hour while pushing the mower. Which of the following is closest to the number of hours it will take Moe to mow the lawn.
Solution
Since the swath Moe actually mows is 
feet wide, he mows 
square feet in one hour. His lawn has an area of 
, so it will take Moe 
hours to finish mowing the lawn. Thus the answer is 
.
See Also
| 2003 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 3 |
Followed by Problem 5 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
| 2003 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
