Difference between revisions of "2003 AMC 10B Problems/Problem 6"
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x&=5.4\end{align*}</cmath> | x&=5.4\end{align*}</cmath> | ||
| − | The horizontal length is <math>5.4\times4=21.6</math>, which is closest to <math>\boxed{\ | + | The horizontal length is <math>5.4\times4=21.6</math>, which is closest to <math>\boxed{\textbf{(D) \ } 21.5}</math>. |
==See Also== | ==See Also== | ||
{{AMC10 box|year=2003|ab=B|num-b=5|num-a=7}} | {{AMC10 box|year=2003|ab=B|num-b=5|num-a=7}} | ||
Revision as of 18:53, 26 November 2011
Problem
Many television screens are rectangles that are measured by the length of their diagonals. The ratio of the horizontal length to the height in a standard television screen is 
. The horizontal length of a "
-inch" television screen is closest, in inches, to which of the following?
Solution
If you divide the television screen into two right triangles, the legs are in the ratio of , and we can let one leg be 
and the other be 
. Then we can use the Pythagorean Theorem.
The horizontal length is 
, which is closest to 
.
See Also
| 2003 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
