Difference between revisions of "2003 AMC 8 Problems/Problem 11"
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== Solution == | == Solution == | ||
On Friday, the shoes would cost <math> 40 \cdot 1.1= 44 </math> dollars. Then on Monday, the shoes would cost <math> 44- \frac{44}{10}=44-4.4=\boxed{\textbf{(B)}\ 39.60} </math>. | On Friday, the shoes would cost <math> 40 \cdot 1.1= 44 </math> dollars. Then on Monday, the shoes would cost <math> 44- \frac{44}{10}=44-4.4=\boxed{\textbf{(B)}\ 39.60} </math>. | ||
| + | |||
| + | == Video Solution == | ||
| + | https://youtu.be/Jh3RJces0CI Soo, DRMS, NM | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2003|num-b=10|num-a=12}} | {{AMC8 box|year=2003|num-b=10|num-a=12}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 23:19, 1 May 2022
Contents
Problem
Business is a little slow at Lou's Fine Shoes, so Lou decides to have a
sale. On Friday, Lou increases all of Thursday's prices by 
percent. Over the
weekend, Lou advertises the sale: "Ten percent off the listed price. Sale
starts Monday." How much does a pair of shoes cost on Monday that
cost 
dollars on Thursday?
Solution
On Friday, the shoes would cost 
dollars. Then on Monday, the shoes would cost 
.
Video Solution
https://youtu.be/Jh3RJces0CI Soo, DRMS, NM
See Also
| 2003 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
