Difference between revisions of "2004 AMC 10A Problems/Problem 16"
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==Solution== | ==Solution== | ||
| − | There | + | There are: |
| + | *<math>1</math> of the <math>1\times 1</math> squares containing the black square, | ||
| + | *<math>4</math> of the <math>2\times 2</math> squares containing the black square, | ||
| + | *<math>9</math> of the <math>3\times 3</math> squares containing the black square, | ||
| + | *<math>4</math> of the <math>4\times 4</math> squares containing the black square, | ||
| + | *<math>1</math> of the <math>5\times 5</math> squares containing the black square. | ||
| − | + | Thus, the answer is <math>1+4+9+4+1=19\Rightarrow \boxed{\mathrm{(D)}}</math>. | |
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| − | <math>1+4+9+4+1=19\Rightarrow \boxed{\mathrm{(D) | ||
==See also== | ==See also== | ||
{{AMC10 box|year=2004|ab=A|num-b=15|num-a=17}} | {{AMC10 box|year=2004|ab=A|num-b=15|num-a=17}} | ||
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| + | [[Category:Introductory Combinatorics Problems]] | ||
Revision as of 17:43, 15 April 2008
Problem
The 
grid shown contains a collection of squares with sizes from 
to . How many of these squares contain the black center square?
Solution
There are:
of the 
squares containing the black square,
of the 
squares containing the black square,
of the 
squares containing the black square,- of the
squares containing the black square, - of the
squares containing the black square.
of the 
of the 
squares containing the black square,
of the 
squares containing the black square,
squares containing the black square,Thus, the answer is 
.
See also
| 2004 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 15 |
Followed by Problem 17 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
