Difference between revisions of "2004 AMC 10A Problems/Problem 9"
(New page: ==Problem== In the figure, <math>\angle EAB</math> and <math>\angle ABC</math> are right angles. <math>AB=4, BC=6, AE=8</math>, and <math>AC</math> and <math>BE</math> intersect at <math>D...) |
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==Solution== | ==Solution== | ||
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== See also == | == See also == | ||
* [http://www.artofproblemsolving.com/Forum/viewtopic.php?t=131320 AoPS topic] | * [http://www.artofproblemsolving.com/Forum/viewtopic.php?t=131320 AoPS topic] | ||
{{AMC10 box|year=2004|ab=A|num-b=8|num-a=10}} | {{AMC10 box|year=2004|ab=A|num-b=8|num-a=10}} | ||
Revision as of 10:19, 15 January 2008
Problem
In the figure, 
and 
are right angles. 
, and 
and 
intersect at 
. What is the difference between the areas of 
and 
?
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
| 2004 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 8 |
Followed by Problem 10 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
