Difference between revisions of "2004 AMC 10B Problems/Problem 1"

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Start from Row 12 to row 22. There are 11 rows in total.
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==Problem==
33*11 = 363; (C)
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Each row of the Misty Moon Amphitheater has <math>33</math> seats. Rows <math>12</math> through <math>22</math> are reserved for a youth club. How many seats are reserved for this club?
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<math> \mathrm{(A) \ } 297 \qquad \mathrm{(B) \ } 330\qquad \mathrm{(C) \ } 363\qquad \mathrm{(D) \ } 396\qquad \mathrm{(E) \ } 726 </math>
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==Solution==
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There are <math>22-12+1=11</math> rows of <math>33</math> seats, giving <math>11\times 33=\boxed{\mathrm{(C)}\ 363}</math> seats.
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== See also ==
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{{AMC10 box|year=2004|ab=B|before=First Question|num-a=2}}
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{{MAA Notice}}

Latest revision as of 20:59, 22 July 2014

Problem

Each row of the Misty Moon Amphitheater has $33$ seats. Rows $12$ through $22$ are reserved for a youth club. How many seats are reserved for this club?

$\mathrm{(A) \ } 297 \qquad \mathrm{(B) \ } 330\qquad \mathrm{(C) \ } 363\qquad \mathrm{(D) \ } 396\qquad \mathrm{(E) \ } 726$

Solution

There are $22-12+1=11$ rows of $33$ seats, giving $11\times 33=\boxed{\mathrm{(C)}\ 363}$ seats.

See also

2004 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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