Difference between revisions of "2004 AMC 10B Problems/Problem 3"

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==Solution==
 
==Solution==
  
At the fourth practice she made <math>48/2=24</math> throws, at the third one it was <math>24/2=12</math>, then we get <math>12/2=6</math> throws for the second practice, and finally <math>6/2=3\Rightarrow\boxed{A}</math> throws at the first one.
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At the fourth practice she made <math>48/2=24</math> throws, at the third one it was <math>24/2=12</math>, then we get <math>12/2=6</math> throws for the second practice, and finally <math>6/2=3\Rightarrow\boxed{\mathrm{(A)}\ 3}</math> throws at the first one.
  
 
== See also ==
 
== See also ==

Latest revision as of 21:02, 22 July 2014

Problem

At each basketball practice last week, Jenny made twice as many free throws as she made at the previous practice. At her fifth practice she made $48$ free throws. How many free throws did she make at the first practice?

$\mathrm{(A) \ } 3 \qquad \mathrm{(B) \ } 6 \qquad \mathrm{(C) \ } 9 \qquad \mathrm{(D) \ } 12\qquad \mathrm{(E) \ } 15$

Solution

At the fourth practice she made $48/2=24$ throws, at the third one it was $24/2=12$, then we get $12/2=6$ throws for the second practice, and finally $6/2=3\Rightarrow\boxed{\mathrm{(A)}\ 3}$ throws at the first one.

See also

2004 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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