2004 AMC 10B Problems/Problem 5
Revision as of 02:50, 6 February 2009 by Professorhong (talk | contribs) (New page: D =0; A must be determined either 3 or 2. 3^2 > 2^3, thus A is 3. B then follows to be 2 and C = 1. The result is 9, (D))
D =0; A must be determined either 3 or 2. 3^2 > 2^3, thus A is 3. B then follows to be 2 and C = 1. The result is 9, (D)
