2004 AMC 12A Problems/Problem 3
Problem
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See Also
| 2004 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 2 |
Followed by Problem 4 |
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| All AMC 12 Problems and Solutions | |
The answer is (B) since x can't be 0, which leaves only 49 different values for y.
