Difference between revisions of "2004 AMC 8 Problems/Problem 7"

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== Solution ==
 
== Solution ==
The maximum heart rate is <math>220-26=194</math> beats per minute. The target heart rate is then <math>0.8*194 \approx 155</math> beats per minute. <math>\boxed{\textbf{(B)}\ 155}</math>
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The maximum heart rate is <math>220-26=194</math> beats per minute. The target heart rate is then <math>0.8*194 \approx \boxed{\textbf{(B)}\ 155}</math> beats per minute.
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==See Also==
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{{AMC8 box|year=2004|num-b=6|num-a=8}}
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{{MAA Notice}}

Latest revision as of 00:55, 5 July 2013

Problem

An athlete's target heart rate, in beats per minute, is $80\%$ of the theoretical maximum heart rate. The maximum heart rate is found by subtracting the athlete's age, in years, from $220$. To the nearest whole number, what is the target heart rate of an athlete who is $26$ years old?

$\textbf{(A)}\ 134\qquad\textbf{(B)}\ 155\qquad\textbf{(C)}\ 176\qquad\textbf{(D)}\ 194\qquad\textbf{(E)}\ 243$

Solution

The maximum heart rate is $220-26=194$ beats per minute. The target heart rate is then $0.8*194 \approx \boxed{\textbf{(B)}\ 155}$ beats per minute.

See Also

2004 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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