Difference between revisions of "2005 AMC 10A Problems/Problem 5"

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So they get <math>3-2=1</math> additional window if they purchase the windows together.  
 
So they get <math>3-2=1</math> additional window if they purchase the windows together.  
  
Therefore they save <math>1\cdot100=100\Rightarrow A</math>
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Therefore they save <math>1\cdot100=\left(\text{A}\right)100</math>.
  
 
==See also==
 
==See also==

Revision as of 16:25, 21 October 2020

Problem

A store normally sells windows at $100$ each. This week the store is offering one free window for each purchase of four. Dave needs seven windows and Doug needs eight windows. How many dollars will they save if they purchase the windows together rather than separately?

$\mathrm{(A) \ } 100\qquad \mathrm{(B) \ } 200\qquad \mathrm{(C) \ } 300\qquad \mathrm{(D) \ } 400\qquad \mathrm{(E) \ } 500$

Solution

The store's offer means that every $5$th window is free.

Dave would get $\left\lfloor\frac{7}{5}\right\rfloor=1$ free window.

Doug would get $\left\lfloor\frac{8}{5}\right\rfloor=1$ free window.

This is a total of $2$ free windows.

Together, they would get $\left\lfloor\frac{8+7}{5}\right\rfloor = \left\lfloor\frac{15}{5}\right\rfloor=3$ free windows.

So they get $3-2=1$ additional window if they purchase the windows together.

Therefore they save $1\cdot100=\left(\text{A}\right)100$.

See also

2005 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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