Difference between revisions of "2005 AMC 12B Problems/Problem 1"

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== Problem ==
 
== Problem ==
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Two is <math>10\%</math> of <math>x</math> and <math>20\%</math> of <math>y</math>.  What is <math>x-y</math>?
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<math>
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\mathrm{(A)}\ 1      \qquad
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\mathrm{(B)}\ 2      \qquad
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\mathrm{(C)}\ 5      \qquad
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\mathrm{(D)}\ 10      \qquad
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\mathrm{(E)}\ 20
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</math>
  
 
== Solution ==
 
== Solution ==

Revision as of 21:25, 17 April 2009

Problem

Two is $10\%$ of $x$ and $20\%$ of $y$. What is $x-y$?

$\mathrm{(A)}\ 1      \qquad \mathrm{(B)}\ 2      \qquad \mathrm{(C)}\ 5      \qquad \mathrm{(D)}\ 10      \qquad \mathrm{(E)}\ 20$

Solution

See also

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