Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "2005 AMC 12B Problems/Problem 2"

(→‎Problem)
(→‎Solution)
Line 11: Line 11:
  
 
== Solution ==
 
== Solution ==
 +
 +
<math>2x+7=3 \Rightarrow 2x = -4 \Rightarrow = -2</math>.
 +
 +
<math>-2b-10=-2 \Rightarrow -2b = 8 \Rightarrow b = \boxed{-4}</math>.
  
 
== See also ==
 
== See also ==
 
* [[2005 AMC 12B Problems]]
 
* [[2005 AMC 12B Problems]]

Revision as of 21:35, 17 April 2009

Problem

The equations $2x+7=3$ and $bx-10=-2$ have the same solution for $x$. What is the value of $b$?

$\mathrm{(A)}\ -8 \qquad \mathrm{(B)}\ -4 \qquad \mathrm{(C)}\ -2 \qquad \mathrm{(D)}\ 4 \qquad \mathrm{(E)}\ 8$

Solution

$2x+7=3 \Rightarrow 2x = -4 \Rightarrow = -2$.

$-2b-10=-2 \Rightarrow -2b = 8 \Rightarrow b = \boxed{-4}$.

See also

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2005_AMC_12B_Problems/Problem_2&oldid=31346"