Difference between revisions of "2005 AMC 12B Problems/Problem 4"
M1sterzer0 (talk | contribs) (→Problem) |
M1sterzer0 (talk | contribs) (→Solution) |
||
| Line 11: | Line 11: | ||
== Solution == | == Solution == | ||
| + | Lisa's goal was to get an A on <math>80\% \cdot 50 = 40</math> quizzes. She already has A's on <math>22</math> quizzes, so she needs to get A's on <math>40-22=18</math> more. There are <math>50-30=20</math> quizzes left, so she can afford to get less than an A on <math>20-18=\boxed{2}</math> of them. | ||
== See also == | == See also == | ||
* [[2005 AMC 12B Problems]] | * [[2005 AMC 12B Problems]] | ||
Revision as of 22:17, 17 April 2009
Problem
At the beginning of the school year, Lisa's goal was to earn an A on at least 
of her 
quizzes for the year. She earned an A on 
of the first 
quizzes. If she is to achieve her goal, on at most how many of the remaining quizzes can she earn a grade lower than an A?
Solution
Lisa's goal was to get an A on 
quizzes. She already has A's on quizzes, so she needs to get A's on 
more. There are 
quizzes left, so she can afford to get less than an A on 
of them.
