Difference between revisions of "2005 AMC 8 Problems/Problem 1"
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==Solution== | ==Solution== | ||
| − | If <math>x</math> is the number, then <math>2x=60</math> and <math>x=30</math>. | + | If <math>x</math> is the number, then <math>2x=60</math> and <math>x=30</math>. Dividing the number by <math>2</math> yields <math>30/2 = \boxed{\textbf{(B)}\ 15}</math>. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2005|before=First <br/> Question|num-a=2}} | {{AMC8 box|year=2005|before=First <br/> Question|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 14:28, 10 October 2015
Problem
Connie multiplies a number by 2 and gets 60 as her answer. However, she should have divided the number by 2 to get the correct answer. What is the correct answer?
Solution
If 
is the number, then 
and 
. Dividing the number by 
yields 
.
See Also
| 2005 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
