Difference between revisions of "2005 AMC 8 Problems/Problem 6"

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==See Also==
 
{{AMC8 box|year=2005|num-b=5|num-a=7}}
 
{{AMC8 box|year=2005|num-b=5|num-a=7}}
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Latest revision as of 18:23, 24 September 2016

Problem

Suppose $d$ is a digit. For how many values of $d$ is $2.00d5 > 2.005$?

$\textbf{(A)}\ 0\qquad\textbf{(B)}\ 4\qquad\textbf{(C)}\ 5\qquad\textbf{(D)}\ 6\qquad\textbf{(E)}\ 10$

Solution

We see that $2.0055$ works but $2.0045$ does not. The digit $d$ can be from $5$ through $9$, which is $\boxed{\textbf{(C)}\ 5}$ values.

See Also

2005 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png