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2005 Alabama ARML TST Problems/Problem 6

Revision as of 14:50, 17 November 2006 by Solafidefarms (talk | contribs) (awupued)
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Problem

How many of the positive divisors of 3,240,000 are perfect cubes?

Solution

$3240000=2^63^45^4$. We want to know how many numbers are in the form $2^{3a}3^{3b}5^{3c}$, $a\leq 2A$,$b\leq 1$, $c\leq 1$; there are 12 such numbers, if we count 1 as a perfect cube.

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