2005 CEMC Gauss (Grade 7) Problems/Problem 10

Revision as of 01:46, 23 October 2014 by RTG (talk | contribs) (See Also)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

In relation to Smiths Falls, Ontario, the local time in St. John’s, Newfoundland, is $90$ minutes ahead, and the local time in Whitehorse, Yukon, is $3$ hours behind. When the local time in St. John’s is 5:36 p.m., the local time in Whitehorse is

$\text{(A)}$ 1:06 p.m. $\text{(B)}$ 2:36 p.m. $\text{(C)}$ 4:06 p.m. $\text{(D)}$ 12:06 p.m. $\text{(E)}$ 10:06 p.m.

Solution

When it is 5:36 p.m. in St. John’s, it is $90$ minutes or $3/2$ hours earlier in Smiths Falls, so it is 4:06 p.m. in Smiths Falls. When it is 4:06 p.m. in Smiths Falls, it is 3 hours earlier in Whitehorse, so it is 1:06 p.m. in Whitehorse. The answer is $A$.

See Also

2005 CEMC Gauss (Grade 7) (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 7)