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2006 AIME I Problems/Problem 7

Revision as of 19:22, 11 March 2007 by K1c2h2o (talk | contribs) (→‎Solution)

Problem

An angle is drawn on a set of equally spaced parallel lines as shown. The ratio of the area of shaded region $\mathcal{C}$ to the area of shaded region $\mathcal{B}$ is 11/5. Find the ratio of shaded region $\mathcal{D}$ to the area of shaded region $\mathcal{A}.$



Solution

Let: The set of parallel lines...perpendicular to x-axis & cross x-axis at 0, 1, 2... The base of area A is at x = 1. One side of the angle be the x-axis. The other side be y = x-h... as point of the angle isn't on parallel lines Then... $Area C / Area B = 11 / 5 = [.5(5-h)^2 - .5(4-h)^2] / [.5(3-h)^2 - .5(2-h)^2] Thus h = 5/6$ By similar method, D/A seems to be 408.

See also

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