Difference between revisions of "2006 AMC 10A Problems/Problem 3"

(Redirect)
 
(4 intermediate revisions by 4 users not shown)
Line 1: Line 1:
== Problem ==
+
#redirect [[2006 AMC 12A Problems/Problem 3]]
The ratio of Mary's age to Alice's age is 3:5.  Alice is 30 years old.  How many years old is Mary?
 
 
 
<math> \mathrm{(A) \ } 15\qquad \mathrm{(B) \ } 18\qquad \mathrm{(C) \ } 20\qquad \mathrm{(D) \ } 24\qquad \mathrm{(E) \ } 50 </math>
 
== Solution ==
 
We can create the ratio
 
 
 
<math>\frac{3}{5}=\frac{x}{30}</math>
 
 
 
Where ''x'' is Mary's age. Simplfying yields
 
 
 
<math>(3)(30)=5x\Longrightarrow 90=5x\Longrightarrow x=18, (B)</math>
 
== See Also ==
 
*[[2006 AMC 10A Problems]]
 

Latest revision as of 23:03, 27 April 2008

Invalid username
Login to AoPS