Difference between revisions of "2006 AMC 10A Problems/Problem 3"

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== Problem ==
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#redirect [[2006 AMC 12A Problems/Problem 3]]
The ratio of Mary's age to Alice's age is 3:5.  Alice is 30 years old.  How many years old is Mary?
 
 
 
<math> \mathrm{(A) \ } 15\qquad \mathrm{(B) \ } 18\qquad \mathrm{(C) \ } 20\qquad \mathrm{(D) \ } 24\qquad \mathrm{(E) \ } 50 </math>
 
== Solution ==
 
We can create the equation
 
 
 
<math>\frac{3}{5}=\frac{x}{30}</math>
 
 
 
Where ''x'' is Mary's age. Simplfying yields
 
 
 
<math>(3)(30)=5x\Longrightarrow 90=5x\Longrightarrow x=18, (B)</math>
 
 
 
== See Also ==
 
*[[2006 AMC 10A Problems]]
 
 
 
*[[2006 AMC 10A Problems/Problem 2|Previous Problem]]
 
 
 
*[[2006 AMC 10A Problems/Problem 4|Next Problem]]
 
 
 
[[Category:Introductory Algebra Problems]]
 

Latest revision as of 23:03, 27 April 2008

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