# Difference between revisions of "2006 AMC 10A Problems/Problem 7"

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== Problem == | == Problem == | ||

− | + | {{image}} | |

− | The <math> | + | The <math>8\times18</math> [[rectangle]] <math>ABCD</math> is cut into two congruent hexagons, as shown, in such a way that the two hexagons can be repositioned without overlap to form a square. What is <math>y</math>? |

<math> \mathrm{(A) \ } 6\qquad \mathrm{(B) \ } 7\qquad \mathrm{(C) \ } 8\qquad \mathrm{(D) \ } 9\qquad \mathrm{(E) \ } 10 </math> | <math> \mathrm{(A) \ } 6\qquad \mathrm{(B) \ } 7\qquad \mathrm{(C) \ } 8\qquad \mathrm{(D) \ } 9\qquad \mathrm{(E) \ } 10 </math> | ||

== Solution == | == Solution == | ||

− | Since the two [[hexagon]]s are going to be repositioned to form a [[square]] without overlap, the [[area]] will remain the same. The rectangle's area is 18 | + | Since the two [[hexagon]]s are going to be repositioned to form a [[square (geometry) | square]] without overlap, the [[area]] will remain the same. The rectangle's area is <math>18\cdot8=144</math>. This means the square will have four sides of length 12. The only way to do this is shown below.<br> |

[[Image:Square.JPG]] | [[Image:Square.JPG]] | ||

− | As you can see from the diagram, the [[line segment]] denoted as | + | As you can see from the diagram, the [[line segment]] denoted as <math>y</math> is actually half as long as the side of the square, which leads one to conclude that its value is <math>\frac{12}{2} = 6 \Longrightarrow \mathrm{(A)}</math>. |

## Revision as of 16:45, 17 October 2006

## Problem

*An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.*

The rectangle is cut into two congruent hexagons, as shown, in such a way that the two hexagons can be repositioned without overlap to form a square. What is ?

## Solution

Since the two hexagons are going to be repositioned to form a square without overlap, the area will remain the same. The rectangle's area is . This means the square will have four sides of length 12. The only way to do this is shown below.

As you can see from the diagram, the line segment denoted as is actually half as long as the side of the square, which leads one to conclude that its value is .