Difference between revisions of "2006 AMC 10B Problems/Problem 9"
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== Solution == | == Solution == | ||
| − | The calorie to gram ratio of Francesca's lemonade is <math>\frac{25+386+0}{100+100+400}=\frac{ | + | The calorie to gram ratio of Francesca's lemonade is <math>\frac{25+386+0}{100+100+400}=\frac{411\textrm{calories}}{600\textrm{grams}}=\frac{137\textrm{calories}}{200\textrm{grams}}</math> |
| − | So in <math> | + | So in <math>200\textrm{grams}</math> of Francesca's lemonade there are <math>200\textrm{grams}\cdot\frac{137\textrm{calories}}{200\textrm{grams}}=137\textrm{calories} \Rightarrow B</math> |
== See Also == | == See Also == | ||
*[[2006 AMC 10B Problems]] | *[[2006 AMC 10B Problems]] | ||
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| + | *[[2006 AMC 10B Problems/Problem 8|Previous Problem]] | ||
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| + | *[[2006 AMC 10B Problems/Problem 10|Next Problem]] | ||
Revision as of 14:58, 2 August 2006
Problem
Francesca uses 100 grams of lemon juce, 100 grams of sugar, and 400 grams of water to make lemonade. There are 25 calories in 100 grams of lemon juice and 386 calories in 100 grams of sugar. Water contains no calories. How many calories are in 200 grams of her lemonade?
Solution
The calorie to gram ratio of Francesca's lemonade is 
So in 
of Francesca's lemonade there are 
