Difference between revisions of "2006 AMC 12A Problems/Problem 2"

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== Solution ==
 
== Solution ==
  
Using the definition of <math>\otimes</math>, we have <math>h\otimes h=h^{3}-h</math>.  Then <math>h\otimes (h\otimes h)=h\otimes (h^{3}-h)=h^{3}-(h^{3}-h)=h</math>.  The answer is C.
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By the definition of <math>\otimes</math>, we have <math>h\otimes h=h^{3}-h</math>.  Then <math>h\otimes (h\otimes h)=h\otimes (h^{3}-h)=h^{3}-(h^{3}-h)=h</math>.  The answer is C.
  
 
== See also ==
 
== See also ==
 
* [[2006 AMC 12A Problems]]
 
* [[2006 AMC 12A Problems]]

Revision as of 22:03, 11 July 2006

Problem

Define $x\otimes y=x^3-y$. What is $h\otimes (h\otimes h)$?

$\mathrm{(A) \ } -h\qquad \mathrm{(B) \ } 0\qquad \mathrm{(C) \ } h\qquad \mathrm{(D) \ } 2h$

$\mathrm{(E) \ }  h^3$

Solution

By the definition of $\otimes$, we have $h\otimes h=h^{3}-h$. Then $h\otimes (h\otimes h)=h\otimes (h^{3}-h)=h^{3}-(h^{3}-h)=h$. The answer is C.

See also