Difference between revisions of "2006 AMC 12A Problems/Problem 5"

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== Solution ==
 
== Solution ==
  
Each slice of plain pizza costs <math>\frac{1}{8}\cdot 8=1</math> dollarEach slice of anchovy pizza costs <math>1+\frac{1}{4}\cdot 2=\frac{3}{2}</math> dollars.  Dave paid <math>4\cdot\frac{3}{2}+1\cdot 1=7</math> dollars, and Doug paid <math>3\cdot 1=3</math> dollars.  Dave paid <math>7-3=4</math> dollars than Doug.  The answer is D.
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Dave and Doug paid <math>8+2=10</math> dollars in totalDoug paid for three slices of plain pizza, which cost <math>\frac{3}{8}\cdot 8=3</math>.  Dave paid <math>10-3=7</math> dollars.  Dave paid <math>7-3=4</math> more dollars than Doug.  The answer is D.
  
 
== See also ==
 
== See also ==
 
* [[2006 AMC 12A Problems]]
 
* [[2006 AMC 12A Problems]]

Revision as of 14:00, 12 July 2006

Problem

Doug and Dave shared a pizza with $8$ equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half the pizza. The cost of a plain pizza was $8$, and there was an additional cost of $2$ for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each paid for what he had eaten. How many more dollars did Dave pay than Doug?

$\mathrm{(A) \ } 1\qquad \mathrm{(B) \ } 2\qquad \mathrm{(C) \ } 3\qquad \mathrm{(D) \ } 4\qquad \mathrm{(E) \ }  5$

Solution

Dave and Doug paid $8+2=10$ dollars in total. Doug paid for three slices of plain pizza, which cost $\frac{3}{8}\cdot 8=3$. Dave paid $10-3=7$ dollars. Dave paid $7-3=4$ more dollars than Doug. The answer is D.

See also