Difference between revisions of "2006 AMC 12A Problems/Problem 8"
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== Solution == | == Solution == | ||
| − | 1+2+3+4+5 = 15 | + | 1+2+3+4+5 = 15; 4+5+6 = 15; 7+8 = 15 |
| − | 4+5+6 = 15 | ||
| − | 7+8 = 15 | ||
| − | The correct answer is C | + | The correct answer is C (3) |
== See also == | == See also == | ||
Revision as of 20:49, 30 January 2007
Problem
How many sets of two or more consecutive positive integers have a sum of 
?
Solution
1+2+3+4+5 = 15; 4+5+6 = 15; 7+8 = 15
The correct answer is C (3)
