Difference between revisions of "2006 AMC 12B Problems/Problem 4"

Line 13: Line 13:
 
<math>\frac{1.95}{20}=.0975 \Rightarrow \text{(C)}</math>
 
<math>\frac{1.95}{20}=.0975 \Rightarrow \text{(C)}</math>
 
== See also ==
 
== See also ==
* [[2006 AMC 12B Problems]]
+
{{AMC12 box|year=2006|ab=B|num-b=3|num-a=5}}

Revision as of 09:06, 14 November 2007

Problem

Mary is about to pay for five items at the grocery store. The prices of the items are $$ 7.99, $$ 4.99, $$ 2.99, $$ 1.99, and $$ 0.99. Mary will pay with a twenty-dollar bill. Which of the following is closest to the percentage of the $$20.00 that she will receive in change?

$\text {(A) } 5 \qquad \text {(B) } 10 \qquad \text {(C) } 15 \qquad \text {(D) } 20 \qquad \text {(E) } 25$

Solution

The total price of the items is $(8-.01)+(5-.01)+(3-.01)+(2-.01)+(1-.01)=19-.05=18.05$

$20-18.05=1.95$

$\frac{1.95}{20}=.0975 \Rightarrow \text{(C)}$

See also

2006 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions
Invalid username
Login to AoPS